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SOLUTION #1 - SQUARES FIRST, CARL DIVIDES HIS AS TO RESERVE TO HIMSELF ONE-FOURTH IN THE FORM OF A SQUARE. THEN, CARL TAKES THE REMAINING 3/4 SHAPE AND SCALES IT DOWN BY 1/4. HE THEN, MULTIPLIES THE SHAPE INTO 4 IDENTICALLY SHAPED PIECES, AND ARANGES THEM SO THAT THEY FIT INTO THE ORIGINAL 3/4 SHAPE. SOLUTION #2 - RECTANGLES FIRST, CREATE A TRIANGLE THAT IS 1/4 THE SIZE OF THE SQUARE. NOW, WITH STRAIGHT LINES, CREATE TWO SQUARES. PROCEED TO DISECT THE TWO SQUARES WITH HORIZONTAL LINES CREATING 4 TRIANGLES. THEN, DISECT ONE OF THE RESULTUING TRIANGLES FROM EACH SQUARE. THE SHAPE OF LAND FOR EACH OF HIS FOUR CHILDREN IS DIVIDED EVENLY AND IS THE SAME SHAPE THE CRIMINAL SHOULD OPEN DOOR NUMBER 2. IF THE 1ST STATEMENT IS TRUE, THEN THE 2ND STATEMENT WILL ALSO BE TRUE. SO WE CAN CONCLUDE THAT THE 2ND STATEMENT IS TRUE AND THE 1ST STATEMENT IS FALSE. FROM THE 2ND STATEMENT, WE KNOW THAT THERE IS A LADY IN ONE OF THE ROOMS AND A TIGER IS IN THE OTHER ROOM. THE LADY HAS TO BE BEHIND DOOR 2 AS THE FIRST STATEMENT IS NOT TRUE FILL THE 5 OZ. AND 11 OZ. CONTAINERS FROM THE 24 OZ. CONTAINER. THIS LEAVES 8 OZ. IN THE 24 OZ. BOTTLE. NEXT EMPTY THE 11 OZ. BOTTLE BY POURING THE CONTENTS INTO THE 13 OZ. BOTTLE. FILL THE 13 OZ. BOTTLE FROM THE 5 OZ. CONTAINER (WITH 2 OZ.) AND PUT THE REMAINING 3 OZ. IN THE 11 OZ. BOTTLE. THIS LEAVES THE 5 OZ. CONTAINER EMPTY. NOW POUR 5 OZ. FROM THE 13 OZ. BOTTLE INTO THE 5 OZ. BOTTLE LEAVING 8 OZ. IN THE 13 OZ. BOTTLE. FINALLY POUR THE 5 OZ. BOTTLE CONTENTS INTO THE 11 OZ. BOTTLE GIVING 8 OZ. IN THIS CONTAINER A = 3.5 B = 4.5 C = 9.5 D = 3.5 TO SOLVE THE PUZZLE, YOU WILL NEED TO COME UP WITH 4 EQUATIONS: A + B = 8 ... (1) C - D = 6 ... (2) A + C = 13 ... (3) B + D = 8 ... (4) SUBTRACTING (1) FROM (3) GIVES: C - B = 5 ... (5) ADDING (2) TO (4) GIVES: B + C = 14 ... (6) ADDING (5) AND (6) GIVES: 2C = 19 C = 9.5 SUBSTITUTING C = 9.5 IN (2) GIVES: 9.5 - D = 6 D = 3.5 SUBSTITUTING D = 3.5 IN (4), GIVES: B + 3.5 = 8 B = 4.5 SUBSTITUTING B = 4.5 IN (1), GIVES: A + 4.5 = 8 A = 3.5