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0 / 60 seg.
Can you place 10 coins in 3 cups so that each cup contains an odd number of coins?
L
_
T
'
S
N
_
M
_
T
H
_
C
_
P
S
A
,
B
_
N
D
C
.
P
L
_
C
_
3
C
_
_
N
S
_
N
C
_
P
A
_
N
D
2
C
_
_
N
S
_
N
C
_
P
B
.
P
L
_
C
_
C
_
P
A
_
N
C
_
P
B
,
N
_
W
C
_
P
B
C
_
N
T
_
_
N
S
5
C
_
_
N
S
.
P
L
_
C
_
R
_
M
_
_
N
_
N
G
5
C
_
_
N
S
_
N
C
_
P
C
Clue
MAKE 2 PILES WITH EQUAL NUMBER OF COINS. NOW, FLIP ALL THE COINS IN ONE OF THE PILE. HOW THIS WILL WORK? LET'S TAKE A LOOK AT AN EXAMPLE. SO INITIALLY THERE ARE 5 HEADS, SO SUPPOSE YOU DIVIDE IT IN 2 PILES. P1 : H H T T T P2 : H H H T T NOW WHEN PILE P1 IS FLIPPED: P1 : T T H H H THE NUMBER OF HEADS IN P1 AND P2 ARE EQUAL NOW
CREATE TWO GROUPS OF TEN COINS, THEN FLIP OVER THE COINS IN ONE OF THE GROUPS
LET'S NAME THE CUPS A, B AND C. PLACE 3 COINS IN CUP A AND 2 COINS IN CUP B. PLACE CUP A IN CUP B, NOW CUP B CONTAINS 5 COINS. PLACE REMAINING 5 COINS IN CUP C
NO MATTER IN WHICH POSITION THE CUP IS, ITS HANDLE WILL ALWAYS BE ON THE OUTSIDE
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