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0 / 60 seg.
Can you place 10 coins in 3 cups so that each cup contains an odd number of coins?
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A
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B
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N
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3
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N
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N
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A
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2
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N
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B
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W
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5
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R
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C
Clue
YOU WILL NEED 4 COINS. PLACE THREE COINS FLAT ON THE TABLE IN A TRIANGLE (TOUCHING EACH OTHER) AND PUT THE FOURTH ONE ON TOP OF THEM IN THE MIDDLE
LET'S NAME THE CUPS A, B AND C. PLACE 3 COINS IN CUP A AND 2 COINS IN CUP B. PLACE CUP A IN CUP B, NOW CUP B CONTAINS 5 COINS. PLACE REMAINING 5 COINS IN CUP C
HE WILL HAVE 25 COCONUTS WITH HIM AT THE END. THE TRICK IS TO REDUCE THE NUMBER OF SACKS AS YOU PASS CHECKPOINTS. THE FIRST 10 CHECKPOINTS REQUIRE 3 COCONUTS EACH, WHICH EMPTIES HIS FIRST SACK. THE NEXT 15 CHECKPOINTS REQUIRE 2 COCONUTS EACH, WHICH WILL EMPTY HIS SECOND STACK. NOW, HE IS LEFT WITH 1 SACK AND 5 MORE CHECKPOINTS. SO, THE 5 CHECKPOINTS WILL TAKE 1 COCONUT EACH. THEREFORE, HE WILL BE LEFT WITH 25 COCONUTS
9 PERFORMANCES. WE CAN HAVE A PERFORMANCE THE FIRST DAY, AND THEN EVERY THIRD DAY AFTER THAT, GIVING 8 MORE PERFORMANCES. THE TOTAL IS 1 + 8 = 9
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