1 4 2 8 5 7 .
T H _
N _ M B _ R
_ N D
T H _
S _ M S
W _ L L
_ N L Y
C _ N T _ _ N
T H _
D _ G _ T S
1 , 2 , 4 , 5 , 7
_ N D
8 .
1 4 2 8 5 7
+
1 4 2 8 5 7
=
2 8 5 7 1 4
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
4 2 8 5 7 1
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
5 7 1 4 2 8
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
7 1 4 2 8 5
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
8 5 7 1 4 2
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
9 9 9 9 9 9 Clue
3. 3 SQUARED IS 9. 3+9=12. TAKE THE TWO DIGITS OF THE SUMMATION AND ADD THEM; 1+2=3. IN SHORT; 3-9-12-3. THIS CAN ALSO WORK WITH THE NUMBER 0 AND 9 142857. THE NUMBER AND THE SUMS WILL ONLY CONTAIN THE DIGITS 1,2,4,5,7 AND 8. 142857 + 142857 = 285714 142857 + 142857 + 142857 = 428571 142857 + 142857 + 142857 + 142857 = 571428 142857 + 142857 + 142857 + 142857 + 142857 = 714285 142857 + 142857 + 142857 + 142857 + 142857 + 142857 = 857142 142857 + 142857 + 142857 + 142857 + 142857 + 142857 + 142857 = 999999 THE PROFESSOR HAS TO ADD THE REST OF THE DIGITS, FIND THE NEAREST NUMBER TO THE SUM THAT IS DIVISIBLE BY 9 AND GET THE DIFFERENCE. SO, JOHN GAVE THE NUMBER 9646 TO THE PROFESSOR. THE PROFESSOR WILL ADD THE NUMBERS (9 + 6 + 4 + 6) TO GET 25. THE NEAREST NUMBER TO 25 THAT IS DIVISIBLE BY 9 IS 27. AND THE CROSSED OUT NUMBER IS 27 - 25. THIS IS A MATHS TRICK THAT RELIES ON THE POWER OF 9 IF YOU FOLLOWED ALL THE STEPS APART FROM THE LAST ONE THERE WILL BE THREE OPTIONS REMAINING: 64, 84, AND 86. YOU THEN HAD TO ADD UP THE DIGITS, 64=6+4=10, 84=8+4=12, AND 86=8+6=14. FINALLY, YOU THEN HAD TO TAKE UP THE MIDDLE BIGGEST NUMBER (12) AND PUT IT BACK AS IT WAS BEFORE THE DIGITS WERE ADDED TOGETHER AND YOUR ANSWER SHOULD BE 84