1 4 2 8 5 7 .
T H _
N _ M B _ R
_ N D
T H _
S _ M S
W _ L L
_ N L Y
C _ N T _ _ N
T H _
D _ G _ T S
1 , 2 , 4 , 5 , 7
_ N D
8 .
1 4 2 8 5 7
+
1 4 2 8 5 7
=
2 8 5 7 1 4
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
4 2 8 5 7 1
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
5 7 1 4 2 8
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
7 1 4 2 8 5
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
8 5 7 1 4 2
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
+
1 4 2 8 5 7
=
9 9 9 9 9 9 Clue
3. 3 SQUARED IS 9. 3+9=12. TAKE THE TWO DIGITS OF THE SUMMATION AND ADD THEM; 1+2=3. IN SHORT; 3-9-12-3. THIS CAN ALSO WORK WITH THE NUMBER 0 AND 9 142857. THE NUMBER AND THE SUMS WILL ONLY CONTAIN THE DIGITS 1,2,4,5,7 AND 8. 142857 + 142857 = 285714 142857 + 142857 + 142857 = 428571 142857 + 142857 + 142857 + 142857 = 571428 142857 + 142857 + 142857 + 142857 + 142857 = 714285 142857 + 142857 + 142857 + 142857 + 142857 + 142857 = 857142 142857 + 142857 + 142857 + 142857 + 142857 + 142857 + 142857 = 999999 THE SECRET CODE IS 7,4,6,5,8. LET THE NUMBERS = A, B, C, D, E BASED ON 1ST CLUE: E + C = 14 BASED ON 2ND CLUE: A = 2B - 1 BASED ON 3RD CLUE: D = B + 1 BASED ON 4TH CLUE: B + C = 10 BASED ON 5TH CLUE: A + B + C + D + E = 30 ALL NUMBERS CAN BE REPRESENTED BY B EXCEPT FOR E SO WE NEED TO REWRITE EQUATION 1. SUBSTITUTE C = 10 - B FROM EQUATION 4 INTO EQUATION 1. E + (10 - B) = 14 E = B + 4 SUBSTITUTE A,C,D,E IN EQUATION 5 (2B - 1) + B + (10 - B) + (B + 1) + (B + 4) = 30 SOLVING FOR B GIVES 4. USE THE OTHER EQUATIONS TO FIND THE VALUES OF A,C,D AND E THE PROFESSOR HAS TO ADD THE REST OF THE DIGITS, FIND THE NEAREST NUMBER TO THE SUM THAT IS DIVISIBLE BY 9 AND GET THE DIFFERENCE. SO, JOHN GAVE THE NUMBER 9646 TO THE PROFESSOR. THE PROFESSOR WILL ADD THE NUMBERS (9 + 6 + 4 + 6) TO GET 25. THE NEAREST NUMBER TO 25 THAT IS DIVISIBLE BY 9 IS 27. AND THE CROSSED OUT NUMBER IS 27 - 25. THIS IS A MATHS TRICK THAT RELIES ON THE POWER OF 9