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E M P T Y
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W _ T _ R Clue
JIM AND WANDA HAVE 7 AND 5 APPLES RESPECTIVELY. TO SOLVE USING MATHS, LET J AND W BE THE NUMBER OF APPLES OF JIM AND WANDA RESPECTIVELY. IF JIM GIVES WANDA AN APPLE, THEY WILL BOTH HAVE THE SAME NUMBER OF APPLES: W + 1 = J - 1 IF WANDA GIVES JIM AN APPLE, JIM WILL HAVE TWICE AS MANY AS WANDA: 2(W - 1) = J + 1 SOLVING THE EQUATIONS WILL GIVE J=7 AND W=5 A TOTAL OF NINE COINS ARE NEEDED: FOUR (1¢) PENNIES, ONE (5¢) NICKEL, TWO (10¢) DIMES, ONE (25¢) QUARTER AND ONE (50¢) HALF-DOLLAR FILL UP THE THREE-GALLON JUG AND POUR IT INTO THE FIVE-GALLON JUG. DO IT AGAIN AND THERE WILL BE ONE GALLON LEFT IN THE THREE-GALLON JUG. EMPTY THE FIVE-GALLON JUG AND POUR IN THE ONE GALLON OF WATER FROM THE THREE-GALLON JUG. FILL THE THREE-GALLON JUG WITH WATER AGAIN AND POUR IT INTO THE FIVE-GALLON JUG. THE FIVE-GALLON JUG SHOULD NOW CONTAIN 4 GALLONS OF WATER THE PROBABILITY IS 1/2. THERE ARE INITIALLY 4 POSSIBILITIES: GIRL-GIRL, GIRL-BOY, BOY-GIRL AND BOY-BOY. SINCE THE OLDER CHILD IS A BOY, WE CAN RULE OUT THE GIRL-GIRL AND GIRL-BOY COMBINATIONS