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M _ D N _ G H T Clue
THE TIME IS 6AM. FOR EVERY 1 HOUR THAT HAS PASSED, THE CLOCK WILL ONLY SHOW 36 MINUTES AS IT WILL LOSE 24 MINUTES. WHEN THE CLOCK WAS SHOWING 3AM, 180 CLOCK MINUTES HAVE PASSED SINCE MIDNIGHT. THIS MEANS THAT 300 (180/36 X 24 MINUTES + 180 MINUTES) REAL MINUTES HAVE PASSED WHEN THE CLOCK WAS SHOWING 3AM. SINCE THE CLOCK STOPPED 1 HOUR AGO, ANOTHER 60 MINUTES HAVE PASSED. THEREFORE A TOTAL OF 360 MINUTES HAVE PASSED. SINCE 360 MINUTES = 6 HOURS, THE TIME IS 6 HOURS AFTER MIDNIGHT IN 3 1/2 HOURS THE ALARM CLOCK HAS BECOME 14 MINUTES SLOW. AT NOON THE ALARM CLOCK WILL FALL BEHIND APPROXIMENTLY AN ADDITIONAL MINUTE. ITS HANDS WILL SHOW NOON IN 15 MINUTES IN 60 DAYS. IF ONE CLOCK GAINS A MINUTE A DAY (OR LOSES, THE MATH WILL BE THE SAME), IT WILL GAIN 24 MINUTES THE FIRST DAY, 48 MINUTES BY THE END OF THE SECOND, AND 120 MINUTES AFTER 5 DAYS. THIS MEANS IN TEN DAYS IT WILL GAIN 4 HOURS AND IN 20 DAYS, 8 HOURS. THIS TIMES 3, TO MAKE IT 24 HOURS, WILL REQUIRE 60 DAYS. THE OTHER CLOCK RUNNING BACKWARD WILL TELL THE SAME TIME AS THE NORMAL CLOCK EVERY 24 HOURS, SO IT REALLY DOESN'T PRESENT A PROBLEM FOR THE SOLUTION OF THE PUZZLE BEFORE I LEFT, I WOUND THE WALL CLOCK. WHEN I RETURNED, THE CHANGE IN TIME EQUALED HOW LONG IT TOOK TO GO TO MY FRIENDS HOUSE AND RETURN, PLUS THE TIME I SPENT THERE. BUT I KNEW THE LATTER BECAUSE I LOOKED AT MY FRIENDS WATCH WHEN I ARRIVED AND LEFT. SUBTRACTING THE TIME OF THE VISIT FROM THE TIME I WAS ABSENT FROM MY HOUSE, AND DIVIDING BY 2, I OBTAINED THE TIME IT TOOK ME TO RETURN HOME. I ADDED THIS TIME TO WHAT MY FRIEND WATCH SHOWED WHEN I LEFT, AND SET THE SUM ON MY WALL CLOCK