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THE DIFFERENCE BETWEEN THE REAL TIME AND THE TIME OF THE MIRROR IMAGE IS TWO HOURS AND TEN MINUTES (TWO AND A HALF HOURS, MINUS THE TWENTY MINUTES OF CYCLING). THEREFORE, THE ORIGINAL TIME ON THE CLOCK AT HOME THAT MORNING COULD ONLY HAVE BEEN FIVE MINUTES PAST SEVEN: THE DIFFERENCE BETWEEN THESE CLOCKS IS EXACTLY 2 HOURS AND TEN MINUTES (NOTE THAT ALSO FIVE MINUTES PAST ONE CAN BE MIRRORED IN A SIMILAR WAY, BUT THIS IS NOT IN THE MORNING!). CONCLUSION: THE BOY REACHES SCHOOL AT FIVE MINUTES PAST SEVEN PLUS TWENTY MINUTES OF CYCLING, WHICH IS TWENTY-FIVE MINUTES PAST SEVEN!.. HE LEAVES HIS HOUSE AT 7.15 AND REACHES SCHOOL AT 8.15. FROM THE MACHINE AND TRACTOR STATION TO THE RAILROAD STATION IS 1/3 - 1/4 = 1/12 OF THE WAY. BORIS WALKS IT IN 5 MINUTES, SO THE WHOLE TRIP TAKES 1 HOUR. ONE-FOURTH OF THE WAY IS 15 MINUTES. SO HE LEAVES HIS HOUSE AT 7:15 AND REACHES SCHOOL AT 8:15 AS THE PROBLEM SAYS THE APPRENTICE MIXED UP THE HANDS SO THAT THE MINUTE HAND WAS SHORT AND THE HOUR HAND WAS LONG. THE FIRST TIME THE APPRENTICE RETURNED TO THE CLIENT WAS ABOUT 2 HOURS AND 10 MINUTES AFTER HE HAD SET THE CLOCK AT SIX.THE LONG HAD MOVED OLNY FROM TWELVE TO A LITTLE PAST TWO. THE LITTLE MADE TWO WHOLE CIRCLES AND AN ADDITIONAL 10 MINUTES. THUS THE CLOCK SHOWED THE CORRECT TIME. THE NEXT DAY AROUND 7:O5 A.M.HE CAME A SECOND TIME,13 HOURS AND 15 MINUTES AFTER HE HAD SET THE CLOCK FOR SIX. THE LONG HAD, ACTING AS THE HOUR HAND,COVERED 13 HOURS TO REACH 1. THE SHORT HAND MADE 13 FULL CIRCLES AND 5 MINUTES, REACHING 7, SO THE CLOCK SHOWED THE CORRECT TIME AGAIN THE STUDENT IS DOUBLE COUNTING A LOT OF THE DAYS. A LOT OF THE TIME SPENT SLEEPING, EATING, AND RELAXING OCCURS DURING WEEKENDS AND THE SUMMER. WEEKENDS ALSO OCCUR DURING THE SUMMER, SO ALL OF THESE HOURS ARE GETTING COUNTED SEVERAL TIMES. AND, SCHOOL IS NOT AN ALL DAY AFFAIR. SO THE 4 DAYS ACTUALLY REPRESENTS MORE DAYS OF SCHOOL. IF SCHOOL IS 6 HOURS PER DAY, THOSE FOUR DAYS REPRESENTS 16 DAYS OF SCHOOL