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KOLKHOZ IS 120 MILES AWAY FROM THE CITY AND THE TRUCK SHOULD TRAVEL AT 24 MILES AN HOUR. AT 30 MILES PER HOUR A TRUCK TRAVELS A MILE IN 2 MINUTES; AT 20 MILES PER HOUR, IN 3 MINUTES. AT THE LATTER SPEED THE TRUCK IS 1 MINUTE SLOWER PER MILE. TO LOSE 2 HOURS, OR 120 MINUTES, TAKES 120 MILES, WHICH IS HOW FAR THE KOLHOZ IS FROM THE CITY. AT 30 MPH, THE TRUCK WOULD COVER 120 MILES IN 4 HOURS. THE TRIP IS TO TAKE 1 HOUR LONGER, OR TO ARRIVE AT 11:00 A.M., AND CALLS FOR A SPEED OF 24 (120/5) MILES PER HOUR THE FLY WOULD HAVE TRAVELLED 90 MILES. THE TRAINS ARE 100 MILES APART, AND THE TRAINS ARE TRAVELLING TOWARD EACH OTHER AT 40 AND 60 MPH, THE TRAINS WILL MEET IN ONE HOUR. THE FLY WILL HAVE BEEN FLYING FOR AN HOUR AT 90 MPH AT THAT POINT, SO THE FLY WILL HAVE TRAVELLED 90 MILES THE TRAIN IS ABOUT TO LEAVE AND YOU WILL NOT BE ABLE TO CATCH THE TRAIN. THE AMOUNT OF TIME TAKEN TO TRAVEL TO THE HALFWAY POINT AT 15 MILES AN HOUR IS THE SAME AMOUNT OF TIME TAKEN TO REACH THE TRAIN STATION WHEN TRAVELLING TO THE RAILROAD STATION AT 30 MILES AN HOUR. FOR EXAMPLE, LET'S ASSUME THAT THE DISTANCE TO TRAVEL IS 30 MILES. WHEN TRAVELLING AT 30 MILES AN HOUR, IT TAKES 1 HOUR. WHEN TRAVELLING AT 15 MILES AN HOUR, IT WILL ALREADY TAKE 1 HOUR TO REACH THE HALFWAY POINT THERE IS NO WAY TO GET AN AVERAGE SPEED OF 30 MPH (MILES PER HOUR). IF YOUR AVERAGE SPEED FOR THE 2 MILES STRETCH MUST BE 30 MPH, YOU SHOULD DO IT IN 4 MINUTES. DURING THE ASCENT, YOU WOULD HAVE ALREADY TAKEN 4 MINUTES TO TRAVEL 1 MILE AT 15 MPH. SINCE YOU HAVE TAKEN 4 MINUTES TO GO UP THE HILL, YOU WILL NEED TO TAKE 0 SECONDS TO TRAVEL THE 1 MILE DESCENT IN ORDER TO GET AN AVERAGE SPEED OF 30 MPH. THIS IS NOT POSSIBLE