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6 Clue
ZOE'S SMALLEST POSSIBLE NUMBER IS 6. BASED ON THE FIRST STATEMENT OF ALI, IT INDICATES THAT HE HAS NEITHER 1 NOR 9. IF HE HAD EITHER 1 OR 9 THEN HE WOULD KNOW THAT ZOE MUST HAVE A BIGGER OR SMALLER NUMBER. NOW ZOE, BASED ON ALI'S FIRST STATEMENT, KNOWS THAT ALI DOESN'T HAVE 1 OR 9. ZOE'S FIRST STATEMENT INDICATES THAT SHE DOES NOT HAVE 2 OR 8 (NEITHER 1 NOR 9). IF SHE HAD 1, 2, 8 OR 9, THEN SHE COULD HAVE CONCLUDED THAT ALI HAS A BIGGER OR SMALLER NUMBER. NOW ALI KNOWS THAT ZOE DOESN'T HAVE 1, 2, 8 OR 9. ALI'S SECOND STATEMENT INDICATES THAT HE DOES NOT HAVE 3 OR 7 AND ALSO NOT 1, 2, 8 OR 9. ZONE CAN CONCLUDE THAT ALI DOESN'T HAVE 1, 2, 3, 7, 8 OR 9. IN SHORT, ALI MUST HAVE EITHER 4, 5 OR 6. NOW WHEN ZOE SAYS THAT SHE HAS A BIGGER NUMBER THEN IT MUST BE EITHER 6, 7, 8 OR 9 AND ALI HAVING 4 OR 5. ZOE CAN'T SAY CONFIDENTLY THAT SHE HAS A BIGGER NUMBER IF SHE HAD A 4 OR 5, AS IT COULD BE SMALLER THAN WHAT ALI COULD HAVE. SO ZOE'S SMALLEST POSSIBLE NUMBER IS A 6 THE ADDRESS IS 1460 SUNSET BOULEVARD. YOU KNOW THAT THE HOUSE NUMBERS ARE EVEN AND CONSECUTIVE, SO THEY MUST BE APPROXIMATELY 1/6TH THE VALUE OF THE SUM 8790. IN FACT, THE NUMBER THAT IS 1/6TH THE TOTAL IS THE MEAN (AVERAGE) FOR ALL 6 HOUSES. THE AVERAGE NUMBER IS 1465 (8790 / 6). THERE MUST BE 3 HOUSE NUMBERS GREATER THAN THAT NUMBER, AND 3 HOUSE NUMBERS LESS THAN THAT NUMBER, ALL BEING EVEN AND CONSECUTIVE. THEREFORE, THE 6 HOUSE NUMBERS ARE 1460, 1462, 1464, 1466, 1468, 1470. THE LOWEST HOUSE NUMBER, AS PER THE QUESTION, IS THE ANSWER: 1460 THE CHILDREN ARE 1, 6 AND 6 YEARS OLD. THE PRODUCT OF THEIR AGES IS 36, SO NONE OF THEM CAN BE OLDER THAN 36. THE NUMBER 36 HAS TO BE EXPRESSED AS THE PRODUCT OF 3 NUMBERS. THEIR POSSIBLE AGES ARE (THE SUM OF THEIR AGES IS IN BRACKETS): 1, 1, 36 (3938) 1, 2, 18 (21) 1, 3, 12 (16) 1, 4, 9 (14) 1, 6, 6 (13) 2, 2, 9 (13) 2, 3, 6 (11) 3, 3, 4 (10) SINCE CHERYL IS TOM'S NEXT DOOR NEIGHBOUR, TOM KNOWS CHERYL'S HOUSE NUMBER. TOM WOULD KNOW THE CHILDREN'S AGES IN EVERY CASE THAT SUMS UP TO A UNIQUE NUMBER EXCEPT FOR THE SUM OF 13, WHICH HAVE 2 COMBINATIONS OF POSSIBLE AGES. AS A RESULT, TOM WOULD BE CONFUSED AS HE HAS TO PICK BETWEEN THE 2 COMBINATIONS: (1,6,6) AND (2,2,9). CHERYL THEN TELLS TOM ABOUT HER YOUNGEST CHILD WHO LIKES STRAWBERRY MILK WHICH TELLS TOM THAT THERE IS ONLY 1 YOUNGEST CHILD FIRST WEIGHING: FOUR AGAINST FOUR SECOND WEIGHING: TWO AGAINST TWO THIRD WEIGHING: ONE AGAINST ONE LET'S NAME THE BALLS 1-12. FIRST WE WEIGH {1,2,3,4} ON THE LEFT AND {5,6,7,8} ON THE RIGHT. THERE ARE THREE SCENARIOS WHICH CAN ARISE FROM THIS. IF THEY BALANCE, THEN WE KNOW 9, 10, 11 OR 12 IS ODD. WEIGH {8, 9} AND {10, 11} (NOTE: 8 IS NOT ODD) IF THEY BALANCE, WE KNOW 12 IS THE ODD ONE. JUST WEIGH IT WITH ANY OTHER BALL AND FIGURE OUT IF IT IS LIGHTER OR HEAVIER. IF {8, 9} IS HEAVIER, THEN EITHER 9 IS HEAVY OR 10 IS LIGHT OR 11 IS LIGHT. WEIGH {10} AND {11}. IF THEY BALANCE, 9 IS ODD (HEAVIER). IF THEY DON'T BALANCE THEN WHICHEVER ONE IS LIGHTER IS ODD (LIGHTER). IF {8, 9} IS LIGHTER, THEN EITHER 9 IS LIGHT OR 10 IS HEAVY OR 11 IS HEAVY. WEIGH {10} AND {11}. IF THEY BALANCE, 9 IS ODD (LIGHTER). IF THEY DON'T BALANCE THEN WHICHEVER ONE IS HEAVIER IS ODD (HEAVIER). IF {1,2,3,4} IS HEAVIER, WE KNOW EITHER ONE OF {1,2,3,4} HEAVIER OR ONE OF {5,6,7,8} IS LIGHTER BUT IT IS GUARANTEED THAT {9,10,11,12} ARE NOT ODD. WEIGH {1,2,5} AND {3,6,9} (NOTE: 9 IS NOT ODD). IF THEY BALANCE, THEN EITHER 4 IS HEAVY OR 7 IS LIGHT OR 8 IS LIGHT. FOLLOWING THE LAST STEP FROM THE PREVIOUS CASE, WE WEIGH {7} AND {8}. IF THEY BALANCE, 4 IS ODD (HEAVIER). IF THEY DON'T BALANCE THEN WHICHEVER ONE IS LIGHTER IS ODD (LIGHTER). IF {1,2,5} IS HEAVIER, THEN EITHER 1 IS HEAVY OR 2 IS HEAVY OR 6 IS LIGHT. WEIGH {1} AND {2}. IF THEY BALANCE, 6 IS ODD (LIGHTER). IF THEY DON'T BALANCE THEN WHICHEVER ONE IS HEAVIER IS ODD (HEAVIER). IF {3,6,9} IS HEAVIER, THEN EITHER 3 IS HEAVY OR 5 IS LIGHT. WEIGH {5} AND {9}. THEY WON'T BALANCE. IF {5} IS LIGHTER, 5 IS ODD (LIGHTER). IF THEY BALANCE, 3 IS ODD (HEAVIER). IF {5,6,7,8} IS HEAVIER, IT IS THE SAME SITUATION AS IF {1,2,3,4} WAS HEAVIER. JUST PERFORM THE SAME STEPS USING 5,6,7 AND 8. WEIGH {5,6,1} AND {7,2,9} (NOTE: 9 IS NOT ODD). IF THEY BALANCE, THEN EITHER 8 IS HEAVY OR 3 IS LIGHT OR 4 IS LIGHT. WE WEIGH {3} AND {4}. IF THEY BALANCE, 8 IS ODD (HEAVIER). IF THEY DON'T BALANCE THEN WHICHEVER ONE IS LIGHTER IS ODD (LIGHTER). IF {5,6,1} IS HEAVIER, THEN EITHER 5 IS HEAVY OR 6 IS HEAVY OR 2 IS LIGHT. WEIGH {5} AND {6}. IF THEY BALANCE, 2 IS ODD (LIGHTER). IF THEY DON'T BALANCE THEN WHICHEVER ONE IS HEAVIER IS ODD (HEAVIER). IF {7,2,9} IS HEAVIER, THEN EITHER 7 IS HEAVY OR 1 IS LIGHT. WEIGH {1} AND {9}. IF THEY BALANCE, 7 IS ODD (HEAVIER). IF THEY DON'T BALANCE THEN 1 IS ODD (LIGHTER). NOTE: THERE ARE OTHER POSSIBLE SOLUTIONS TO THIS PROBLEM AS WELL