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0 / 60 seg.
A boy and a girl each have a bag of containing the same number of jelly beans. How many jelly beans must the boy give the girl so that the girl will have ten more jelly beans than the boy?
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Clue
THE CONTENTS OR THE TEN ENVELOPES (IN DOLLAR BILLS) SHOULD BE AS FOLLOWS: $1, 2, 4, 8, 16, 32, 64, 128, 256, 489. THE FIRST NINE NUMBERS ARE IN GEOMETRICAL PROGRESSION, AND THEIR SUM, DEDUCTED FROM 1,000, GIVES THE CONTENTS OF THE TENTH ENVELOPE
THE BOY MUST GIVE THE GIRL FIVE JELLY BEANS, NOT TEN. HE WOULD THEN HAVE FIVE LESS, AND SHE WOULD HAVE FIVE MORE, AND THE DIFFERENCE BETWEEN THEM WOULD BE TEN
HE WAS BORN ON FEB 29 ON A LEAP YEAR. LEAP YEARS NORMALLY ONLY HAPPEN ONCE EVERY 4 YEARS
THERE ARE FOUR FEET IN THE BARN, CATS HAVE PAWS, NOT FEET
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