T H _
L _ T T _ R
F .
L _ T ' S
W _ R K
B _ C K W _ R D S .
S _ ,
L _ T ' S
S T _ R T
W _ T H
T H _
L _ T T _ R
C
_ N D
F _ _ R
T _
T H _
R _ G H T
_ F
C
_ S
G .
T _
T H _
R _ G H T
_ F
G
_ S
H .
F _ _ R
T _
T H _
L _ F T
_ F
H
_ S
D .
F _ N _ L L Y ,
T W _
T _
T H _
R _ G H T
_ F
D
_ S
F Clue
THEY WILL NEVER STEP OUT WITH RIGHT FEET TOGETHER. FOR EVERY THREE STEPS, THEY WILL BOTH STEP OUT TOGETHER. BUT THE SEQUENCE WILL BE (SHORT MAN-TALL MAN) LEFT-LEFT, RIGHT-LEFT, LEFT-LEFT, RIGHT-LEFT AND SO ON THEY ARE EITHER: 2 OF SPADES, 5 OF SPADES AND 2 OF CLUB; OR 5 OF SPADES, 2 OF SPADES AND 5 OF CLUB THEY STOLE 301 DIAMONDS IN TOTAL. WE NEED A NUMBER THAT IS A MULTIPLE OF 7 THAT WILL GIVE A REMAINDER OF 1 WHEN DIVIDED BY 2, 3, 4, 5, AND 6. THE LEAST COMMON MULTIPLE OF THESE NUMBERS IS 60. SO, WE NEED A MULTIPLE OF 7 THAT IS 1 GREATER THAN A MULTIPLE OF 60. 60 + 1 = 61, NOT A MULTIPLE OF 7 60 X 2 + 1 = 121, NOT A MULTIPLE OF 7 60 X 3 + 1 = 181, NOT A MULTIPLE OF 7 60 X 4 + 1 = 241, NOT A MULTIPLE OF 7 60 X 5 + 1 = 301, A MULTIPLE OF 7 THE LETTER F. LET'S WORK BACKWARDS. SO, LET'S START WITH THE LETTER C AND FOUR TO THE RIGHT OF C IS G. TO THE RIGHT OF G IS H. FOUR TO THE LEFT OF H IS D. FINALLY, TWO TO THE RIGHT OF D IS F