T H _
L _ T T _ R
F .
L _ T ' S
W _ R K
B _ C K W _ R D S .
S _ ,
L _ T ' S
S T _ R T
W _ T H
T H _
L _ T T _ R
C
_ N D
F _ _ R
T _
T H _
R _ G H T
_ F
C
_ S
G .
T _
T H _
R _ G H T
_ F
G
_ S
H .
F _ _ R
T _
T H _
L _ F T
_ F
H
_ S
D .
F _ N _ L L Y ,
T W _
T _
T H _
R _ G H T
_ F
D
_ S
F Clue
25 EGGS WERE BROKEN. THERE IS ONLY ONE WAY OF FINDING A SOLUTION TO THIS PROBLEM: NUMBERS WHICH LEAVE A REMAINDER OF 1, WHEN DIVIDED BY 2: 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35 NUMBERS WHICH LEAVE A REMAINDER OF 1, WHEN DIVIDED BY 3: 4, 7, 10, 13, 16, 19, 22, 25, 28, 31, 34, 37 NUMBERS WHICH LEAVE A REMAINDER OF 1, WHEN DIVIDED BY 4: 5, 9, 13, 17, 21, 25, 29, 33, 37 NUMBERS WHICH LEAVE NO REMAINDER WHEN DIVIDED BY 5: 5, 10, 15, 20, 25, 30, 35 THE ONLY NUMBER FULFILLING THE FOUR CONDITIONS IS 25 B IS THE SISTER-IN-LAW OF E. A IS FATHER OF C AND C IS SISTER OF D. SO, A IS FATHER OF D. BUT D IS SON OF B. SO, B IS THE MOTHER OF D AND WIFE OF A. ALSO, E IS THE BROTHER OF A. SO, B IS THE SISTER-IN-LAW OF E THEY ARE EITHER: 2 OF SPADES, 5 OF SPADES AND 2 OF CLUB; OR 5 OF SPADES, 2 OF SPADES AND 5 OF CLUB THE LETTER F. LET'S WORK BACKWARDS. SO, LET'S START WITH THE LETTER C AND FOUR TO THE RIGHT OF C IS G. TO THE RIGHT OF G IS H. FOUR TO THE LEFT OF H IS D. FINALLY, TWO TO THE RIGHT OF D IS F