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I I Clue
THE MESSENGER HAS TO HAVE TRAVELED 2 KM. IT DOESN'T MATTER WHAT SPEED THEY WALKED AT. AT THE BEGINNING OF THE PUZZLE, THE LINE IS 1 KM LONG. THE GENERAL IS THEREFORE 1 KM AHEAD OF HIM. THE MESSENGER MUST THEREFORE TRAVEL MORE THAN 1 KM TO REACH THE GENERAL. SINCE THE LINE MOVES 1 KM FORWARD, THE END IS WHERE THE BEGINNING WAS. EVEN IF HE WALKED 1.5 KM TO THE GENERAL, HE ONLY HAS TO WALK 0.5 KM TO GET BACK TO THE END OF THE LINE. IT GOES FASTER GOING BACK, BECAUSE NOW THEY ARE COMING TOWARDS HIM, AND NOT GOING AWAY BOTH WILL HAVE THE SAME AMOUNT. LET'S SAY THERE'S 100ML OF TEA AND 100ML OF COFFEE INITIALLY AND THE TEASPOON HOLDS 10ML OF LIQUID. AFTER TRANSFERRING 10ML OF LIQUID FROM THE TEA TO THE COFFEE CUP AND ANOTHER 10ML FROM THE COFFEE TO THE TEA CUP, THE QUANTITY WILL REMAIN THE SAME - 100ML OF COFFEE AND TEA MIX IN THE TEA CUP AND 100ML OF COFFEE AND TEA MIX IN THE COFFEE CUP. SO LET'S SAY AFTER THE MIXING IS DONE THERE IS 99ML OF TEA AND 1ML OF COFFEE IN THE TEA CUP. THE 1ML OF TEA HAS TO BE IN THE COFFEE CUP. THAT MEANS THAT THE COFFEE CUP HAS 99ML OF COFFEE AND 1ML OF TEA. IN OTHER WORDS, IF THERE'S (X)ML OF TEA MISSING FROM THE TEA CUP, THEN THERE HAS TO BE AN EQUAL AMOUNT OF OF COFFEE MISSING FROM THE COFFEE CUP THE BOOKWORM TRAVELLED A DISTANCE OF ONE INCH AND NOT THREE INCHES. IF YOU LOOK AT THE ARRANGEMENT OF THE BOOKS, THE BACK COVER OF VOLUME I IS ON THE LEFT AND THE FRONT COVER OF VOLUME I IS ON THE RIGHT AND NEXT TO THE BACK COVER OF VOLUME II. LIKEWISE, THE BACK COVER OF VOLUME III IS ON THE LEFT AND THE FRONT COVER OF VOLUME III IS ON THE RIGHT. THE DISTANCE BETWEEN THE FRONT COVER OF VOLUME I TO THE BACK COVER OF VOLUME III IS ONLY ONE INCH, WHICH IS THE THICKNESS OF VOLUME II AUDREY WILL REACH THE DESTINATION FIRST. SUPPOSE THEY COVER 12 MILES, BOTH WALKING AT A RATE OF 2 MILES PER HOUR AND RUNNING AT A RATE OF 6 MILES PER HOUR. USE THE FORMULA: RT = D (RATE X TIME = DISTANCE) TO FIND EACH PERSON'S TIME. NANCY (WALKS HALF THE DISTANCE AND RUNS HALF THE DISTANCE): 2T = 6 MILES, SO T = 3 HR. WALKING 6T = 6 MILES, SO T = 1 HR. RUNNING T = 4 HOURS TOTAL TIME AUDREY (WALKS HALF THE TIME AND RUNS HALF THE TIME): 2(0.5T) + 6(0.5T) = 12 MILES T + 3T = 12 4T = 12 T = 3 HOURS TOTAL TIME