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0 / 60 seg.
A smart landscaper is given the task of placing 4 trees so that they are all the same distance away from each other. How does he do this?
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Clue
THE MINIMUM NUMBER OF WEIGHTS REQUIRED IS FIVE AND THESE SHOULD WEIGHT 1, 3, 9, 27 AND 81 POUNDS. THE MERCHANT HAS TO USE A BALANCE WEIGHING SCALE TO DO THE JOB. TO WEIGH 2 POUNDS, HE'LL HAVE TO PUT THE 3 POUND WEIGHT ON ONE PAN AND 1 POUND WEIGHT ON THE OTHER PAN. TO WEIGH 5 POUNDS, HE'LL HAVE TO PUT THE 9 POUND WEIGHT ON ONE PAN AND 1 AND 3 POUND WEIGHTS ON THE OTHER PAN
YOU WILL NEED TO MAKE THREE CUTS. CUT ALL THREE LINKS ON ONE CHAIN AND SEPARATE THEM. NOW YOU HAVE 3 CHAINS AND 3 LINKS. THEN, USE THESE 3 INDIVIDUAL LINKS TO JOIN THE OTHER THREE CHAINS TOGETHER
THE SON WILL CATCH UP WITH HIS FATHER IN 10 MINUTES. IN 10 MINUTES, THE SON WOULD HAVE TRAVELED HALF THE DISTANCE, SINCE HIS TOTAL TRAVELING TIME IS 20 MINUTES. THE FATHER STARTED 5 MINUTES EARLIER THAN THE SON, SO HE WOULD HAVE TRAVELED FOR A TOTAL OF 15 MINUTES WHEN HIS SON REACHED HIM. THEREFORE, THE FATHER WOULD HAVE ALSO TRAVELED HALF THE DISTANCE IN 15 MINUTES
PLACE 3 TREES IN THE VERTEX OF AN EQUILATERAL TRIANGLE. THEN PLACE THE 4TH TREE AT THE TOP AND CENTER OF THE 3, SO THAT IT WILL FORM THE SHAPE OF A PYRAMID OR A TETRAHEDRON
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