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0 / 60 seg.
A smart landscaper is given the task of placing 4 trees so that they are all the same distance away from each other. How does he do this?
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Clue
PLACE 3 TREES IN THE VERTEX OF AN EQUILATERAL TRIANGLE. THEN PLACE THE 4TH TREE AT THE TOP AND CENTER OF THE 3, SO THAT IT WILL FORM THE SHAPE OF A PYRAMID OR A TETRAHEDRON
THE PROBABILITY IS 1/2. THERE ARE INITIALLY 4 POSSIBILITIES: GIRL-GIRL, GIRL-BOY, BOY-GIRL AND BOY-BOY. SINCE THE OLDER CHILD IS A BOY, WE CAN RULE OUT THE GIRL-GIRL AND GIRL-BOY COMBINATIONS
THE SON WILL CATCH UP WITH HIS FATHER IN 10 MINUTES. IN 10 MINUTES, THE SON WOULD HAVE TRAVELED HALF THE DISTANCE, SINCE HIS TOTAL TRAVELING TIME IS 20 MINUTES. THE FATHER STARTED 5 MINUTES EARLIER THAN THE SON, SO HE WOULD HAVE TRAVELED FOR A TOTAL OF 15 MINUTES WHEN HIS SON REACHED HIM. THEREFORE, THE FATHER WOULD HAVE ALSO TRAVELED HALF THE DISTANCE IN 15 MINUTES
YOU WILL NEED TO MAKE THREE CUTS. CUT ALL THREE LINKS ON ONE CHAIN AND SEPARATE THEM. NOW YOU HAVE 3 CHAINS AND 3 LINKS. THEN, USE THESE 3 INDIVIDUAL LINKS TO JOIN THE OTHER THREE CHAINS TOGETHER
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