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0 / 60 seg.
A ship is twice as old as its boiler was when the ship was as old as the boiler is now. What is the ratio of the boiler's age to the ship's age?
R
_
T
_
_
_
S
3
⁄
4
.
I
F
W
_
L
_
T
S
B
_
T
H
_
S
H
_
P
'
S
_
G
_
_
N
D
L
_
T
B
B
_
T
H
_
B
_
_
L
_
R
'
S
_
G
_
,
_
N
D
T
T
_
B
_
T
H
_
D
_
F
F
_
R
_
N
C
_
W
_
G
_
T
:
S
-
T
=
B
S
=
2
X
(
B
-
T
)
I
F
W
_
_
L
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M
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N
_
T
_
T
(
W
_
T
H
T
=
S
-
B
)
,
W
_
W
_
L
L
G
_
T
:
B
⁄
S
=
3
⁄
4
Clue
RATIO IS 3⁄4. IF WE LET S BE THE SHIP'S AGE AND LET B BE THE BOILER'S AGE, AND T TO BE THE DIFFERENCE WE GET: S - T = B S = 2 X (B - T) IF WE ELIMINATE T (WITH T = S - B), WE WILL GET: B⁄S = 3⁄4
"SIX DOZEN DOZEN" IS GREATER. "SIX DOZEN DOZEN" IS 6 X 12 X 12. "HALF DOZEN DOZEN" IS 1/2 X 12 X 12
THE PROBLEM IS THAT THE QUESTION IS CLEVERLY PHRASED TO CAUSE CONFUSION. THE BALANCE TOTAL DOES NOT NEED TO BE EQUAL TO THE WITHDRAWAL TOTAL. AND IN THIS CASE, THE BALANCE TOTAL WILL NOT ADD UP TO SOMETHING MEANINGFUL. LET'S SAY YOU HAVE $100 IN YOUR BANK ACCOUNT AND YOU MAKE 2 WITHDRAWALS OF $1 EACH. THE WITHDRAWAL TOTAL IS $2 ($1 + $1). BUT THE BALANCE TOTAL IS $197 ($99 + $98)
HIS YOUNGER BROTHER WAS 6. LET HIS AGE BE X, DIMPLE'S AGE BE Y, AND HIS FATHER'S AGE BE Z. THEN Z=3Y, Z=X2, Y=2X. SO 6X=X2 AND X=6
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