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0 / 60 seg.
A ship is twice as old as its boiler was when the ship was as old as the boiler is now. What is the ratio of the boiler's age to the ship's age?
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Clue
GRANDFATHER WAS 66 AND GRANDSON WAS 6. WHEN GRANDFATHER WAS 61, GRANSON WAS 1 (61 = 1 X 61) WHEN GRANDFATHER WAS 62, GRANSON WAS 2 (62 = 2 X 31) WHEN GRANDFATHER WAS 63, GRANSON WAS 3 (63 = 3 X 21) WHEN GRANDFATHER WAS 64, GRANSON WAS 4 (64 = 4 X 16) WHEN GRANDFATHER WAS 65, GRANSON WAS 5 (65 = 5 X 13) WHEN GRANDFATHER WAS 66, GRANSON WAS 6 (66 = 6 X 11)
RATIO IS 3⁄4. IF WE LET S BE THE SHIP'S AGE AND LET B BE THE BOILER'S AGE, AND T TO BE THE DIFFERENCE WE GET: S - T = B S = 2 X (B - T) IF WE ELIMINATE T (WITH T = S - B), WE WILL GET: B⁄S = 3⁄4
HE HAD 15 EGGS. THE FIRST PERSON BOUGHT HALF OF THE 15 EGGS WHICH IS 7½ EGGS AND ANOTHER ½ EGG. SO HE BOUGHT 8 EGGS IN TOTAL AND JACK IS LEFT WITH 7 EGGS. THE SECOND PERSON BOUGHT HALF OF THE REMAINING 7 EGGS WHICH IS 3½ EGGS AND ANOTHER ½ EGG. SO HE BOUGHT 4 EGGS AND JACK IS LEFT WITH 3 EGGS. THE LAST PERSON BOUGHT HALF OF THE REMAINING 3 EGGS WHICH IS 1½ EGGS AND ANOTHER ½ EGG. SO THE LAST PERSON BOUGHT 2 EGGS. THAT LEAVES 1 EGG REMAINING IN JACK'S BASKET
HIS YOUNGER BROTHER WAS 6. LET HIS AGE BE X, DIMPLE'S AGE BE Y, AND HIS FATHER'S AGE BE Z. THEN Z=3Y, Z=X2, Y=2X. SO 6X=X2 AND X=6
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