Riddles
Go to...
Index
Translations
Pronunciation
Images
Computers
Geography
Languages
0 / 60 seg.
A ship is twice as old as its boiler was when the ship was as old as the boiler is now. What is the ratio of the boiler's age to the ship's age?
R
_
T
_
_
_
S
3
⁄
4
.
I
F
W
_
L
_
T
S
B
_
T
H
_
S
H
_
P
'
S
_
G
_
_
N
D
L
_
T
B
B
_
T
H
_
B
_
_
L
_
R
'
S
_
G
_
,
_
N
D
T
T
_
B
_
T
H
_
D
_
F
F
_
R
_
N
C
_
W
_
G
_
T
:
S
-
T
=
B
S
=
2
X
(
B
-
T
)
I
F
W
_
_
L
_
M
_
N
_
T
_
T
(
W
_
T
H
T
=
S
-
B
)
,
W
_
W
_
L
L
G
_
T
:
B
⁄
S
=
3
⁄
4
Clue
62.5 GRAMS THE SMALLER BRICK IS NOT ONLY FOUR TIMES SHORTER THAN THE FIRST ONE, BUT IT IS ALSO FOUR TIMES NARROWER AND FOUR TIMES LOWER AND THEREFORE THE RATIO OF THE VOLUME AND WEIGHT IS 4 X 4 X 4 = 64 TIMES. SO 4KG/64 = 62.5 GRAMS
BECAUSE THERE ARE TWO SIDES TO THE COIN, THE CHANCES ARE ALWAYS ONE IN TWO
HIS YOUNGER BROTHER WAS 6. LET HIS AGE BE X, DIMPLE'S AGE BE Y, AND HIS FATHER'S AGE BE Z. THEN Z=3Y, Z=X2, Y=2X. SO 6X=X2 AND X=6
RATIO IS 3⁄4. IF WE LET S BE THE SHIP'S AGE AND LET B BE THE BOILER'S AGE, AND T TO BE THE DIFFERENCE WE GET: S - T = B S = 2 X (B - T) IF WE ELIMINATE T (WITH T = S - B), WE WILL GET: B⁄S = 3⁄4
Text
Audio
Text & audio
Free text
Multiple option
Previous question
Start
Next question
Please enable JavaScript to continue using this application.