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0 / 60 seg.
A ship is twice as old as its boiler was when the ship was as old as the boiler is now. What is the ratio of the boiler's age to the ship's age?
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3
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4
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Clue
TINA WILL BE 97 YEARS OLD WHEN MARK IS 100 YEARS OLD. WHEN TOM WAS 6 YEARS OLD, TINA WAS 3 YEARS OLD. 94 YEARS LATER, HE BECOMES 100 YEARS OLD. AND 94 YEARS LATER, HIS SISTER WILL BE 97 (94 + 3) YEARS OLD
THE JAR WILL BE HALF FULL IN 59 MINUTES. A MINUTE LATER, IT WILL DOUBLE AND WILL FILL THE JAR
HIS YOUNGER BROTHER WAS 6. LET HIS AGE BE X, DIMPLE'S AGE BE Y, AND HIS FATHER'S AGE BE Z. THEN Z=3Y, Z=X2, Y=2X. SO 6X=X2 AND X=6
RATIO IS 3⁄4. IF WE LET S BE THE SHIP'S AGE AND LET B BE THE BOILER'S AGE, AND T TO BE THE DIFFERENCE WE GET: S - T = B S = 2 X (B - T) IF WE ELIMINATE T (WITH T = S - B), WE WILL GET: B⁄S = 3⁄4
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