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0 / 60 seg.
Three kinds of apples are mixed randomly in a box. How many apples must you take out to be sure of having at least two apples of one kind?
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Clue
FOUR. IF THE APPLES ARE A, B, AND C, IT'S POSSIBLE THAT YOU COULD TAKE OUT ONE A, ONE B AND ONE C WITH THREE APPLES, BUT THE FOURTH APPLE MUST BE ONE OF THE THREE KINDS
12 CHESTNUT TREES. THERE ARE 6 CHESTNUT TREES ON EACH SIDE. THE TREES ARE POSITIONED 0 YARDS, 6 YARDS, 12 YARDS, 18 YARDS, 24 YARDS AND 30 YARDS FROM THE START OF THE STREET
SHE NEEDS TO GIVE YOU 5 APPLES. YOU BOTH NEED AT LEAST 5 APPLES TO BEGIN WITH, BUT APART FROM THAT IT DOESN'T MATTER EXACTLY HOW MANY YOU EACH HAVE. WHEN SHE GIVES YOU 5 YOU WILL HAVE 10 MORE THAN HER BECAUSE SHE WILL LOSE 5 AND YOU WILL GAIN 5, RESULTING IN A NET DIFFERENCE OF 10. FOR EXAMPLE, IF BOTH OF YOU HAVE 20 APPLES AND SHE GIVES YOU 5 OF HERS, SHE WILL BE LEFT WITH 15 AND YOU WILL NOW HAVE 25, PRECISELY 10 MORE THAN SHE HAS
JIM AND WANDA HAVE 7 AND 5 APPLES RESPECTIVELY. TO SOLVE USING MATHS, LET J AND W BE THE NUMBER OF APPLES OF JIM AND WANDA RESPECTIVELY. IF JIM GIVES WANDA AN APPLE, THEY WILL BOTH HAVE THE SAME NUMBER OF APPLES: W + 1 = J - 1 IF WANDA GIVES JIM AN APPLE, JIM WILL HAVE TWICE AS MANY AS WANDA: 2(W - 1) = J + 1 SOLVING THE EQUATIONS WILL GIVE J=7 AND W=5
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