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HE HAS TO JUGGLE THEM. AT ANY ONE POINT, THE MAN WILL ONLY BE CARRYING 2 GOLD BARS AND THE OTHER GOLD BAR WILL BE AIRBORNE, MEANING A MAXIMUM OF 95KG TOTAL AT ANY GIVEN TIME FIRST THE BOYS CROSS THE RIVER. ONE STAYS ASHORE WHILE THE OTHER BRINGS THE BOAT TO THE SOLDIERS AND GETS OUT. A SOLDIER GETS IN THE BOAT AND CROSSES. THE BOY WHO HAS STAYED THERE BRINGS THE BOAT BACK TO THE SOLDIERS, THEN TAKES THE OTHER BOY TO THE OTHER SHORE. AGAIN A BOY BRINGS THE BOAT BACK, GETS OUT, A SECOND SOLDIER CROSSES OVER. THIS PROCESS IS REPEATED UNTIL ALL THE SOLDIERS HAVE CROSSED GOLD IS WEIGHED IN TROY OUNCES OR TROY POUNDS, WHERE THERE ARE ONLY 12 TROY OUNCES PER TROY POUND. THE MAXIMUM WEIGHT SPECIFIED ON THE BRIDGE WILL BE USING THE NORMAL IMPERIAL SYSTEM FOR MEASURING WEIGHT, WHERE THERE ARE 16 POUNDS TO AN OUNCE. BECAUSE OF THIS 36 POUNDS OF GOLD (WEIGHED USING THE TROY SYSTEM), WILL ONLY WEIGH ABOUT 29 STANDARD IMPERIAL POUNDS. THIS MEANS THAT HER TOTAL WEIGHT, INCLUDING BOTH GOLD BARS, IS LESS THAN 130 POUNDS. AN ALTERNATIVE ANSWER WOULD BE: THE GIRL WOULD SIMPLY THROW ONE OF THE GOLD BARS UP IN THE AIR WHILE HOLDING THE OTHER IN A JUGGLING MANNER. THUS, SHE WOULD NEVER BE HOLDING MORE THAN 118 POUNDS AS LONG AS SHE THREW THE OPPOSITE BAR UP BEFORE SHE CAUGHT THE OTHER THE TWO SONS GET ON THE BOAT AND ROW BACK TO SHORE. ONE JUMPS OUT AND THE OTHER ROWS BACK TO THE ISLAND AND GETS OUT. THE DAD GETS IN AND RIDES BACK TO SHORE WHERE HE JUMPS OUT AND THE OTHER SON GETS BACK IN. THE SON GOES BACK TO THE ISLAND, FETCHES THE OTHER SON AND TOGETHER THE TWO OF THEM ROW BACK TO THE SHORE