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0 / 60 seg.
My age today is three times what it will be three years from now, minus three times what my age was three years ago. How old am I?
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Clue
HE IS 16 YEARS OLD. WHEN I WAS 4 YEARS OLD, MY BROTHER WAS 2 YEARS OLD (HALF MY AGE), SO MY BROTHER IS 2 YEARS YOUNGER THAN ME. WHEN I AM 18 YEARS OLD, MY BROTHER WILL BE 16 YEARS OLD AS HE IS 2 YEARS YOUNGER THAN ME
18 YEARS OLD. LET MY AGE BE X YEARS NOW. MY AGE AFTER 3 YEARS IS (X+3). MY AGE 3 YEARS AGO IS (X-3). SO, NOW WE CAN COME UP WITH AN EQUATION FOR X: X=3(X+3)-3(X-3) SOLVING FOR X WILL GIVE 18
I AM 19 YEARS OLD AND MY SISTER IS 9. LET X = MY SISTER'S AGE AND Y = MY AGE. Y = X + 10 Y + 1 = 2(X + 1) Y = 2X + 1 SUBSTITUTING THIS RESULT IN OUR FIRST EQUATION, WE HAVE: 2X + 1 = X + 10 X = 9 SO Y = 19 WHEN MY SISTER WAS 5, I WAS 3 TIMES OLDER THAN SHE WAS
DANIEL IS 7 YEARS OLD AND JESSICA IS 4 YEARS OLD. LET X BE THE FATHER'S AGE. SO DANIEL'S AGE IS: X/5 IN 21 YEARS: 21 + X = 2(X/5 + 21) SOLVING FOR X WILL GIVE 35. SINCE DANIEL'S AGE IS X/5: 35/5 = 7 LET Y BE JESSICA'S AGE. SO MOTHER'S AGE IS: 7Y IN 8 YEARS: 7Y + 8 = 3(Y + 8) SOLVING FOR Y WILL GIVE 4
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