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_ N C L _ S _ V _ Clue
THERE ARE 99 RUNNERS IN MATT'S SCHOOL. THIS IS TRICKY. IF MATT IS THE FIFTIETH FASTEST RUNNER, HE WOULD BE NUMBER 50 IN THE SEQUENCE 1, 2, 3...50. TO BE THE FIFTIETH SLOWEST, HE'D HAVE TO BE NUMBER 50 IN THE SEQUENCE 50, 51, 52...99, SINCE THERE ARE FIFTY NUMBERS FROM 50 TO 99 INCLUSIVE TOM WINS AGAIN. IN THE FIRST RACE TOM RAN 100 METERS IN THE TIME IT TOOK HARRY TO RUN 95 METERS. SO IN THE SECOND RACE WHEN HARRY IS AT THE 95 METER MARK TOM WILL ALSO BE THERE (SINCE 100 - 5 = 95). SINCE TOM IS FASTER HE WILL PASS HARRY IN THE LAST 5 METERS OF THE RACE THE PERSON WAS BORN IN 2005 B.C. (BEFORE CHRIST). THEREFORE, HE WAS 5 YEARS OLD IN 2000 B.C, 10 IN 1995 B.C, AND 15 IN 1990 B.C THERE IS NO WAY TO GET AN AVERAGE SPEED OF 30 MPH (MILES PER HOUR). IF YOUR AVERAGE SPEED FOR THE 2 MILES STRETCH MUST BE 30 MPH, YOU SHOULD DO IT IN 4 MINUTES. DURING THE ASCENT, YOU WOULD HAVE ALREADY TAKEN 4 MINUTES TO TRAVEL 1 MILE AT 15 MPH. SINCE YOU HAVE TAKEN 4 MINUTES TO GO UP THE HILL, YOU WILL NEED TO TAKE 0 SECONDS TO TRAVEL THE 1 MILE DESCENT IN ORDER TO GET AN AVERAGE SPEED OF 30 MPH. THIS IS NOT POSSIBLE