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THERE ARE 99 RUNNERS IN MATT'S SCHOOL. THIS IS TRICKY. IF MATT IS THE FIFTIETH FASTEST RUNNER, HE WOULD BE NUMBER 50 IN THE SEQUENCE 1, 2, 3...50. TO BE THE FIFTIETH SLOWEST, HE'D HAVE TO BE NUMBER 50 IN THE SEQUENCE 50, 51, 52...99, SINCE THERE ARE FIFTY NUMBERS FROM 50 TO 99 INCLUSIVE TOM WINS AGAIN. IN THE FIRST RACE TOM RAN 100 METERS IN THE TIME IT TOOK HARRY TO RUN 95 METERS. SO IN THE SECOND RACE WHEN HARRY IS AT THE 95 METER MARK TOM WILL ALSO BE THERE (SINCE 100 - 5 = 95). SINCE TOM IS FASTER HE WILL PASS HARRY IN THE LAST 5 METERS OF THE RACE THE STUDENT IS DOUBLE COUNTING A LOT OF THE DAYS. A LOT OF THE TIME SPENT SLEEPING, EATING, AND RELAXING OCCURS DURING WEEKENDS AND THE SUMMER. WEEKENDS ALSO OCCUR DURING THE SUMMER, SO ALL OF THESE HOURS ARE GETTING COUNTED SEVERAL TIMES. AND, SCHOOL IS NOT AN ALL DAY AFFAIR. SO THE 4 DAYS ACTUALLY REPRESENTS MORE DAYS OF SCHOOL. IF SCHOOL IS 6 HOURS PER DAY, THOSE FOUR DAYS REPRESENTS 16 DAYS OF SCHOOL IT IS IMPOSSIBLE. HE TRAVELLED HALFWAY, WHICH IS 30 KM. HE HAS TO TRAVEL ANOTHER 30 KM. IN TOTAL, HE HAS TO TRAVEL 60 KM WITH AN AVERAGE SPEED OF 60 KM/HOUR - THIS MEANS HIS TOTAL TRAVELLING TIME MUST BE 1 HOUR, BUT HE HAS ALREADY TAKEN 1 HOUR FOR HIS FIRST TRIP. UNLESS HE IS ABLE TO TELEPORT HIMSELF FOR THE SECOND TRIP, HE WILL NEVER BE ABLE TO MAKE IT. SOME SAY THAT HE SHOULD TRAVEL AT 90KM/HOUR FOR THE RETURN TRIP. LET'S WORK IT OUT. FOR THE FIRST TRIP, HE TRAVELLED AT 30KM/HOUR AND COVERED 30KM (HALFWAY TO THE TOWN) IN 1 HOUR. FOR THE SECOND TRIP, IF HE TRAVELLED AT 90KM/HOUR, HE WOULD TAKE 20 MINUTES TO COVER 30KM. HIS TOTAL TRAVELLING TIME WILL BE 1HR AND 20 MINS (80 MINS) AND HE WOULD HAVE TRAVELLED 60KM IN TOTAL. HIS AVERAGE SPEED WOULD BE 45 KM/HOUR AND NOT 60 KM/HOUR