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0 / 60 seg.
If you go to the movies and you're paying, is it cheaper to take one friend to the movies twice, or two friends to the movies at the same time?
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Clue
YES. HE TOOK AS MUCH TIME FOR THE SECOND HALF OF HIS TRIP AS THE WHOLE TRIP WOULD HAVE TAKEN ON FOOT. SO NO MATTER HOW FAST THE TRAIN WAS, HE LOST EXACTLY AS MUCH TIME AS HE SPENT ON THE TRAIN. HE WOULD HAVE SAVED 1⁄30 OF THE TIME BY WALKING ALL THE WAY
THE TRAIN IS ABOUT TO LEAVE AND YOU WILL NOT BE ABLE TO CATCH THE TRAIN. THE AMOUNT OF TIME TAKEN TO TRAVEL TO THE HALFWAY POINT AT 15 MILES AN HOUR IS THE SAME AMOUNT OF TIME TAKEN TO REACH THE TRAIN STATION WHEN TRAVELLING TO THE RAILROAD STATION AT 30 MILES AN HOUR. FOR EXAMPLE, LET'S ASSUME THAT THE DISTANCE TO TRAVEL IS 30 MILES. WHEN TRAVELLING AT 30 MILES AN HOUR, IT TAKES 1 HOUR. WHEN TRAVELLING AT 15 MILES AN HOUR, IT WILL ALREADY TAKE 1 HOUR TO REACH THE HALFWAY POINT
IT'S CHEAPER TO TAKE TWO FRIENDS AT THE SAME TIME. IN THIS CASE, YOU WOULD ONLY BE BUYING THREE TICKETS, WHEREAS IF YOU TAKE THE SAME FRIEND TWICE YOU WOULD NEED TO BUY FOUR TICKETS
66 SECONDS. WHEN THE CLOCK STRUCK SIX, THERE WERE ONLY 5 INTERVALS BETWEEN STROKES, AND EACH INTERVAL WAS 6 (30/5) SECONDS. BETWEEN THE FIRST AND TWELFTH STROKES THERE WILL BE 11 INTERVALS OF 6 SECONDS EACH; THEREFORE, 12 STROKES WILL TAKE 66 SECONDS
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