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0 / 60 seg.
If you change the order of the numbers in my cousin's current age, you'll get her age for next year but doubled. How old is she?
S
H
_
_
S
2
5
Y
_
_
R
S
_
L
D
.
I
F
2
_
N
D
5
C
H
_
N
G
_
P
L
_
C
_
S
,
Y
_
_
W
_
L
L
G
_
T
5
2
.
S
H
_
W
_
L
L
T
_
R
N
2
6
N
_
X
T
Y
_
_
R
,
_
N
D
_
F
Y
_
_
D
_
_
B
L
_
T
H
_
T
N
_
M
B
_
R
,
Y
_
_
W
_
L
L
G
_
T
5
2
Clue
THEY ARE 10.5 AND 0.5 YEARS OLD. A COMMON WRONG ANSWER IS 10 AND 1. THIS IS WRONG BECAUSE THE DIFFERENCE IN AGE WOULD BE 9, NOT 10
THE PATH WAS 5000 PACES LONG. IF THE PATH IS STRAIGHTENED OUT INTO A LINE, ITS AREA EQUALS THE AREA OF THE WHOLE SQUARE, THAT IS, 100 X 100 SQUARE PACES. DIVIDING THE RESULT BY THE WIDTH OF THE PATH GIVES THE LENGTH (OR THE SOLUTION)
SHE IS 25 YEARS OLD. IF 2 AND 5 CHANGE PLACES, YOU WILL GET 52. SHE WILL TURN 26 NEXT YEAR, AND IF YOU DOUBLE THAT NUMBER, YOU WILL GET 52
JACK IS 28, JOHN IS 21. LET A AND B BE JACK'S AND JOHN'S AGE RESPECTIVELY. SO, A + B = 49 THE DIFFERENCE IN THEIR AGES (A - B), ALWAYS REMAIN THE SAME. "WHEN JACK WAS AS OLD AS JOHN IS NOW" MEANS JACK'S AGE WAS B AND JOHN'S AGE HAD TO BE: B - (A - B) = 2B -A JACK IS NOW TWICE THE AGE, SO: A = 2(2B - A) A = 4B - 2A 3A = 4B SUBSTITUTING (A + B = 49), WE CAN GET B = 21 AND A = 28
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