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K M / H _ _ R Clue
IT IS IMPOSSIBLE. HE TRAVELLED HALFWAY, WHICH IS 30 KM. HE HAS TO TRAVEL ANOTHER 30 KM. IN TOTAL, HE HAS TO TRAVEL 60 KM WITH AN AVERAGE SPEED OF 60 KM/HOUR - THIS MEANS HIS TOTAL TRAVELLING TIME MUST BE 1 HOUR, BUT HE HAS ALREADY TAKEN 1 HOUR FOR HIS FIRST TRIP. UNLESS HE IS ABLE TO TELEPORT HIMSELF FOR THE SECOND TRIP, HE WILL NEVER BE ABLE TO MAKE IT. SOME SAY THAT HE SHOULD TRAVEL AT 90KM/HOUR FOR THE RETURN TRIP. LET'S WORK IT OUT. FOR THE FIRST TRIP, HE TRAVELLED AT 30KM/HOUR AND COVERED 30KM (HALFWAY TO THE TOWN) IN 1 HOUR. FOR THE SECOND TRIP, IF HE TRAVELLED AT 90KM/HOUR, HE WOULD TAKE 20 MINUTES TO COVER 30KM. HIS TOTAL TRAVELLING TIME WILL BE 1HR AND 20 MINS (80 MINS) AND HE WOULD HAVE TRAVELLED 60KM IN TOTAL. HIS AVERAGE SPEED WOULD BE 45 KM/HOUR AND NOT 60 KM/HOUR THERE IS NO WAY TO GET AN AVERAGE SPEED OF 30 MPH (MILES PER HOUR). IF YOUR AVERAGE SPEED FOR THE 2 MILES STRETCH MUST BE 30 MPH, YOU SHOULD DO IT IN 4 MINUTES. DURING THE ASCENT, YOU WOULD HAVE ALREADY TAKEN 4 MINUTES TO TRAVEL 1 MILE AT 15 MPH. SINCE YOU HAVE TAKEN 4 MINUTES TO GO UP THE HILL, YOU WILL NEED TO TAKE 0 SECONDS TO TRAVEL THE 1 MILE DESCENT IN ORDER TO GET AN AVERAGE SPEED OF 30 MPH. THIS IS NOT POSSIBLE THE TRAIN IS ABOUT TO LEAVE AND YOU WILL NOT BE ABLE TO CATCH THE TRAIN. THE AMOUNT OF TIME TAKEN TO TRAVEL TO THE HALFWAY POINT AT 15 MILES AN HOUR IS THE SAME AMOUNT OF TIME TAKEN TO REACH THE TRAIN STATION WHEN TRAVELLING TO THE RAILROAD STATION AT 30 MILES AN HOUR. FOR EXAMPLE, LET'S ASSUME THAT THE DISTANCE TO TRAVEL IS 30 MILES. WHEN TRAVELLING AT 30 MILES AN HOUR, IT TAKES 1 HOUR. WHEN TRAVELLING AT 15 MILES AN HOUR, IT WILL ALREADY TAKE 1 HOUR TO REACH THE HALFWAY POINT THERE ARE 99 RUNNERS IN MATT'S SCHOOL. THIS IS TRICKY. IF MATT IS THE FIFTIETH FASTEST RUNNER, HE WOULD BE NUMBER 50 IN THE SEQUENCE 1, 2, 3...50. TO BE THE FIFTIETH SLOWEST, HE'D HAVE TO BE NUMBER 50 IN THE SEQUENCE 50, 51, 52...99, SINCE THERE ARE FIFTY NUMBERS FROM 50 TO 99 INCLUSIVE