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0 / 60 seg.
I have two coins, one is marked George I and one is marked George IV. One is genuine but one is a forgery. Which is the forgery?
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Clue
THERE ARE 2 MEN, 5 WOMEN AND 13 CHILDREN. LET THE NUMBER OF MEN, WOMEN AND CHILDREN BE M, W, AND C RESPECTIVELY. THEN THE PROBLEM STATES THAT: M + W + C = 20 3M + 1.5W + 0.5C = 20 MULTIPLYING EQUATION 2 BY 2 GIVES: 6M + 3W + C = 40 SUBTRACTING THE ABOVE EQUATION FROM THE FIRST EQUATION GIVES: 5M + 2W = 20 THE UNIQUE SOLUTION IS M = 2, W = 5 AND C = 13
FOUR BROTHERS AND THREE SISTERS. EVERY BOY WILL HAVE 3 BROTHERS AND 3 SISTERS. EVERY GIRL WILL HAVE 4 BROTHERS AND 2 (HALF OF THE NUMBER OF BROTHERS) SISTERS
GEORGE I. A COIN WOULD NOT BE MARKED GOERGE I BECAUSE AT THE TIME IT WAS PRODUCED IT WOULD NOT HAVE BEEN KNOWN THAT THERE WAS GOING TO BE A GEORGE II
WHEN YOU ADD TWO HOURS TO ELEVEN O'CLOCK, YOU GET ONE O'CLOCK
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