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0 / 60 seg.
I have five and take away two, yet I am left with four. How is this possible?
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Clue
THEY WILL NEVER STEP OUT WITH RIGHT FEET TOGETHER. FOR EVERY THREE STEPS, THEY WILL BOTH STEP OUT TOGETHER. BUT THE SEQUENCE WILL BE (SHORT MAN-TALL MAN) LEFT-LEFT, RIGHT-LEFT, LEFT-LEFT, RIGHT-LEFT AND SO ON
TAKE THE LETTERS F & E OFF OF THE WORD FIVE. THIS LEAVES YOU WITH IV WHICH IS FOUR IN ROMAN NUMERALS
THEY ARE EITHER: 2 OF SPADES, 5 OF SPADES AND 2 OF CLUB; OR 5 OF SPADES, 2 OF SPADES AND 5 OF CLUB
THE PROBABILITY IS 1/2. THERE ARE INITIALLY 4 POSSIBILITIES: GIRL-GIRL, GIRL-BOY, BOY-GIRL AND BOY-BOY. SINCE THE OLDER CHILD IS A BOY, WE CAN RULE OUT THE GIRL-GIRL AND GIRL-BOY COMBINATIONS
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