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0 / 60 seg.
A girl was eight years old on her first birthday. How could that be?
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Clue
THE PERSON WAS BORN IN 2005 B.C. (BEFORE CHRIST). THEREFORE, HE WAS 5 YEARS OLD IN 2000 B.C, 10 IN 1995 B.C, AND 15 IN 1990 B.C
SHE WAS BORN ON FEBRUARY 29, 1896. THE YEAR 1900 WAS NOT A LEAP YEAR (ONLY CENTURIES DIVISIBLE BY 400 ARE LEAP YEARS), SO THE NEXT FEBRUARY 29 FELL IN 1904 WHEN SHE WAS EIGHT. SHE WAS TWELVE ON HER SECOND BIRTHDAY
THERE ARE 99 RUNNERS IN MATT'S SCHOOL. THIS IS TRICKY. IF MATT IS THE FIFTIETH FASTEST RUNNER, HE WOULD BE NUMBER 50 IN THE SEQUENCE 1, 2, 3...50. TO BE THE FIFTIETH SLOWEST, HE'D HAVE TO BE NUMBER 50 IN THE SEQUENCE 50, 51, 52...99, SINCE THERE ARE FIFTY NUMBERS FROM 50 TO 99 INCLUSIVE
ONLY ONCE. AFTER THAT YOU ARE SUBTRACTING FROM A CARTON THAT NO LONGER HAS 25 EGGS IN IT
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