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0 / 60 seg.
A girl was eight years old on her first birthday. How could that be?
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Clue
THE PERSON WAS BORN IN 2005 B.C. (BEFORE CHRIST). THEREFORE, HE WAS 5 YEARS OLD IN 2000 B.C, 10 IN 1995 B.C, AND 15 IN 1990 B.C
SHE WAS BORN ON FEBRUARY 29, 1896. THE YEAR 1900 WAS NOT A LEAP YEAR (ONLY CENTURIES DIVISIBLE BY 400 ARE LEAP YEARS), SO THE NEXT FEBRUARY 29 FELL IN 1904 WHEN SHE WAS EIGHT. SHE WAS TWELVE ON HER SECOND BIRTHDAY
IT IS NOT POSSIBLE TO GUESS ONLY THREE FRUITS CORRECTLY, THE FOURTH FRUIT WILL BE CORRECT TOO! SO NOBODY HAS GUESSED THREE FRUITS CORRECTLY AND SO 10 (123 - 43 - 39 - 31 = 10) PEOPLE HAVE GUESSED FOUR FRUITS CORRECTLY
"SIX DOZEN DOZEN" IS GREATER. "SIX DOZEN DOZEN" IS 6 X 12 X 12. "HALF DOZEN DOZEN" IS 1/2 X 12 X 12
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