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A farmer has 30 animals consisting of chickens and cows. The animals have 74 legs in total. Find out the number of chickens and cows the farmer has
2
3
C
H
_
C
K
_
N
S
_
N
D
7
C
_
W
S
.
L
_
T
T
H
_
N
_
M
B
_
R
_
F
C
H
_
C
K
_
N
B
_
X
_
N
D
N
_
M
B
_
R
_
F
C
_
W
S
B
_
Y
.
C
H
_
C
K
_
N
S
H
_
V
_
2
_
N
D
C
_
W
S
H
_
V
_
4
L
_
G
S
.
B
_
S
_
D
_
N
T
H
_
S
,
W
_
C
_
N
C
_
M
_
_
P
W
_
T
H
2
_
Q
_
_
T
_
_
N
S
:
2
X
+
4
Y
=
7
4
X
+
Y
=
3
0
S
_
L
V
_
N
G
F
_
R
X
_
N
D
Y
W
_
L
L
G
_
V
_
2
3
_
N
D
7
R
_
S
P
_
C
T
_
V
_
L
Y
Clue
142857. THE NUMBER AND THE SUMS WILL ONLY CONTAIN THE DIGITS 1,2,4,5,7 AND 8. 142857 + 142857 = 285714 142857 + 142857 + 142857 = 428571 142857 + 142857 + 142857 + 142857 = 571428 142857 + 142857 + 142857 + 142857 + 142857 = 714285 142857 + 142857 + 142857 + 142857 + 142857 + 142857 = 857142 142857 + 142857 + 142857 + 142857 + 142857 + 142857 + 142857 = 999999
THERE ARE SIX LEGS ON THE FLOOR. FOUR LEGS FROM THE BED AND YOUR OWN TWO LEGS AS YOU STAND IN THE ROOM. ALL THE ANIMALS ARE ON THE BED AND NOT ON THE FLOOR
23 CHICKENS AND 7 COWS. LET THE NUMBER OF CHICKEN BE X AND NUMBER OF COWS BE Y. CHICKENS HAVE 2 AND COWS HAVE 4 LEGS. BASED ON THIS, WE CAN COME UP WITH 2 EQUATIONS: 2X + 4Y = 74 X + Y = 30 SOLVING FOR X AND Y WILL GIVE 23 AND 7 RESPECTIVELY
THERE ARE MANY POSSIBLE SOLUTIONS ONCE YOU GET THE IDEA. BELOW IS ONE POSSIBLE SOLUTION
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