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0 / 60 seg.
How tall is the table?
T
H
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H
_
_
G
H
T
_
F
T
H
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T
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B
L
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_
S
1
5
0
C
M
.
F
R
_
M
T
H
_
P
_
C
T
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R
_
_
N
T
H
_
L
_
F
T
W
_
H
_
V
_
:
C
_
T
+
T
_
B
L
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-
T
_
R
T
L
_
=
1
7
0
F
R
_
M
T
H
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P
_
C
T
_
R
_
_
N
T
H
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R
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G
H
T
W
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H
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V
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:
T
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R
T
L
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+
T
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B
L
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-
C
_
T
=
1
3
0
A
D
D
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N
G
T
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T
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Q
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T
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N
S
,
W
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G
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T
:
2
(
T
_
B
L
_
)
=
3
0
0
Clue
FOUR. THE FOUR FATHERS COULD BE GRANDFATHERS AND ARE DEFINITELY SONS ALREADY
180 CENTIMETRES. HALF OF HIS HEIGHT IS 90 CENTIMETRES. THEREFORE HIS FULL HEIGHT HAS TO BE DOUBLE OF THAT
THEY WILL NEVER STEP OUT WITH RIGHT FEET TOGETHER. FOR EVERY THREE STEPS, THEY WILL BOTH STEP OUT TOGETHER. BUT THE SEQUENCE WILL BE (SHORT MAN-TALL MAN) LEFT-LEFT, RIGHT-LEFT, LEFT-LEFT, RIGHT-LEFT AND SO ON
THE HEIGHT OF THE TABLE IS 150 CM. FROM THE PICTURE ON THE LEFT WE HAVE: CAT + TABLE - TURTLE = 170 FROM THE PICTURE ON THE RIGHT WE HAVE: TURTLE + TABLE - CAT = 130 ADDING THE TWO EQUATIONS, WE GET: 2(TABLE) = 300
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