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0 / 60 seg.
How many people can read hexadecimal if only you and DEAD people can read it?
5
7
0
0
6
P
_
_
P
L
_
.
T
H
_
T
R
_
C
K
_
S
T
H
_
T
T
H
_
W
_
R
D
"
D
E
A
D
"
R
_
P
R
_
S
_
N
T
S
_
N
_
M
B
_
R
_
N
H
_
X
_
D
_
C
_
M
_
L
.
T
H
_
T
N
_
M
B
_
R
_
N
B
_
S
_
1
0
_
S
5
7
0
0
5
,
_
N
D
_
D
D
_
N
G
_
N
_
M
_
R
_
T
_
_
N
C
L
_
D
_
Y
_
_
R
S
_
L
F
G
_
V
_
S
Y
_
_
5
7
0
0
6
Clue
YES. HE TOOK AS MUCH TIME FOR THE SECOND HALF OF HIS TRIP AS THE WHOLE TRIP WOULD HAVE TAKEN ON FOOT. SO NO MATTER HOW FAST THE TRAIN WAS, HE LOST EXACTLY AS MUCH TIME AS HE SPENT ON THE TRAIN. HE WOULD HAVE SAVED 1⁄30 OF THE TIME BY WALKING ALL THE WAY
57006 PEOPLE. THE TRICK IS THAT THE WORD "DEAD" REPRESENTS A NUMBER IN HEXADECIMAL. THAT NUMBER IN BASE 10 IS 57005, AND ADDING ONE MORE TO INCLUDE YOURSELF GIVES YOU 57006
IT IS NOT POSSIBLE TO GUESS ONLY THREE FRUITS CORRECTLY, THE FOURTH FRUIT WILL BE CORRECT TOO! SO NOBODY HAS GUESSED THREE FRUITS CORRECTLY AND SO 10 (123 - 43 - 39 - 31 = 10) PEOPLE HAVE GUESSED FOUR FRUITS CORRECTLY
THE DIFFERENCE IN AGE IS STILL 23 YEARS, SO I MUST BE 23 IF MY FATHER IS TWICE AS OLD
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