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0 / 60 seg.
How many people can read hexadecimal if only you and DEAD people can read it?
5
7
0
0
6
P
_
_
P
L
_
.
T
H
_
T
R
_
C
K
_
S
T
H
_
T
T
H
_
W
_
R
D
"
D
E
A
D
"
R
_
P
R
_
S
_
N
T
S
_
N
_
M
B
_
R
_
N
H
_
X
_
D
_
C
_
M
_
L
.
T
H
_
T
N
_
M
B
_
R
_
N
B
_
S
_
1
0
_
S
5
7
0
0
5
,
_
N
D
_
D
D
_
N
G
_
N
_
M
_
R
_
T
_
_
N
C
L
_
D
_
Y
_
_
R
S
_
L
F
G
_
V
_
S
Y
_
_
5
7
0
0
6
Clue
IT IS NOT POSSIBLE TO GUESS ONLY THREE FRUITS CORRECTLY, THE FOURTH FRUIT WILL BE CORRECT TOO! SO NOBODY HAS GUESSED THREE FRUITS CORRECTLY AND SO 10 (123 - 43 - 39 - 31 = 10) PEOPLE HAVE GUESSED FOUR FRUITS CORRECTLY
THE PERSON WAS BORN IN 2005 B.C. (BEFORE CHRIST). THEREFORE, HE WAS 5 YEARS OLD IN 2000 B.C, 10 IN 1995 B.C, AND 15 IN 1990 B.C
THE DIFFERENCE IN AGE IS STILL 23 YEARS, SO I MUST BE 23 IF MY FATHER IS TWICE AS OLD
57006 PEOPLE. THE TRICK IS THAT THE WORD "DEAD" REPRESENTS A NUMBER IN HEXADECIMAL. THAT NUMBER IN BASE 10 IS 57005, AND ADDING ONE MORE TO INCLUDE YOURSELF GIVES YOU 57006
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