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0 / 60 seg.
Given two 2s, "plus" can be changed to "times" without changing the results: 2 + 2= 2 x 2. The solution with three numbers is easy too: 1 + 2 + 3= 1 x 2 x 3. Now find the answer for 4 numbers and for 5 numbers
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Clue
THE NUMBERS CAN BE GROUPED BY PAIRS: 999,999,999 AND 0; 999,999,998 AND 1′ 999,999,997 AND 2; AND SO ON.... THERE ARE HALF A BILLION PAIRS, AND THE SUM OF THE DIGITS IN EACH PAIR IS 81. THE DIGITS IN THE UNPAIRED NUMBER, 1,000,000,000, ADD TO 1. THEN: (500,000,000 X 81) + 1= 40,500,000,001
20 TIMES. (8, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 98)
SOLUTION FOR 4 NUMBERS: 1 + 1 + 2 + 4= 1 X 1 X 2 X 4. SOLUTION FOR 5 NUMBERS: 1 + 1 + 1 + 2 + 5= 1 X 1 X 1 X 2 X 4 1 + 1 + 1 + 3 + 3= 1 X 1 X 1 X 2 X 4 1 + 1 +2 + 2 + 2= 1 X 1 X 2 X 2 X 2
20 TIMES. THEY ARE 9, 19, 29, 39, 49, 59, 69, 79, 89, 99 (2 TIMES) FOLLOWED BY 90, 91, 92, 93, 94, 95, 96, 97, 98
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