T H _ R _
M _ Y
M _ N Y
P _ S S _ B L _
S _ L _ T _ _ N S ,
H _ R _
_ S
_
S _ M P L _
_ N _ :
T H _
F _ R S T
P _ R S _ N
T _ K _ S
H _ S
M _ N T H L Y
S _ L _ R Y
( L _ T S
S _ Y
$ 1 0 0 ) ,
_ D D S
_ N
_ R B _ T R _ R Y
_ M _ _ N T
T H _ T
_ N L Y
H _
K N _ W S
( L _ T S
S _ Y
$ 4 7 5 )
_ N D
W H _ S P _ R S
T H _ T
N _ M B _ R
( $ 5 7 5 )
T _
T H _
S _ C _ N D
P _ R S _ N .
T H _
S _ C _ N D
P _ R S _ N
T H _ N
_ D D S
H _ S
M _ N T H L Y
S _ L _ R Y
( L _ T S
S _ Y
$ 1 5 0 )
T _
T H _ T
V _ L _ _
_ N D
W H _ S P _ R S
T H _
N _ W
T _ T _ L
( $ 7 2 5 )
T _
T H _
T H _ R D
P _ R S _ N .
T H _
T H _ R D
P _ R S _ N
_ D D S
_ N
H _ S
S _ L _ R Y ,
W H _ S P _ R S
T H _
N _ W
T _ T _ L
T _
T H _
F _ _ R T H
P _ R S _ N
_ N D
S _
_ N
_ N T _ L
T H _
T _ N T H
P _ R S _ N
_ D D S
_ N
H _ S
S _ L _ R Y
_ N D
W H _ S P _ R S
T H _
F _ N _ L
T _ T _ L
T _
T H _
F _ R S T
P _ R S _ N .
T H _
F _ R S T
P _ R S _ N
T H _ N
S _ B T R _ C T S
H _ S
_ R B _ T R _ R Y
N _ M B _ R
F R _ M
T H _ T
T _ T _ L ,
D _ V _ D _ S
B Y
1 0 ,
W H _ C H
P R _ D _ C _ S
T H _
_ V _ R _ G _
M _ N T H L Y
S _ L _ R Y
F _ R
T H _
G R _ _ P
W _ T H _ _ T
_ N Y _ N _
H _ V _ N G
T _
D _ V _ L G _
T H _ _ R
S _ L _ R Y
T _
_ N Y _ N _
_ L S _ Clue
THE SHEEP WILL SURVIVE. IF THERE WERE 1 LION AND 1 SHEEP, THEN THE LION WOULD SIMPLY EAT THE SHEEP. THE SHEEP WILL NOT SURVIVE. IF THERE WERE 2 LIONS AND 1 SHEEP, THEN NO LION WOULD EAT THE SHEEP, BECAUSE IF ONE OF THEM WOULD, IT WOULD SURELY BE EATEN BY THE OTHER LION AFTERWARDS. THE SHEEP WILL SURVIVE. IF THERE WERE 3 LIONS AND 1 SHEEP, THEN ONE OF THE LIONS COULD SAFELY EAT THE SHEEP, BECAUSE IT WOULD TURN INTO THE SCENARIO WITH 2 LIONS, WHERE NO ONE CAN EAT THE SHEEP. THE SHEEP WILL NOT SURVIVE. IF THERE WERE 4 LIONS AND 1 SHEEP, THEN NO LION WOULD EAT THE SHEEP, BECAUSE IT WOULD TURN INTO THE SCENARIO WITH 3 LIONS. THE SHEEP WILL SURVIVE. CONTINUING THIS ARGUMENT, THE CONCLUSION IS AS FOLLOWS: IF THERE IS AN EVEN NUMBER OF LIONS, THEN NOTHING HAPPENS AND THE SHEEP SURVIVES. IF THERE IS AN ODD NUMBER OF LIONS, THEN ANY LION COULD SAFELY EAT THE SHEEP AND THE SHEEP WILL NOT SURVIVE. THIS IS SIMILAR TO THE UNEXPECTED HANGING PARADOX IT IS IMPOSSIBLE. HE TRAVELLED HALFWAY, WHICH IS 30 KM. HE HAS TO TRAVEL ANOTHER 30 KM. IN TOTAL, HE HAS TO TRAVEL 60 KM WITH AN AVERAGE SPEED OF 60 KM/HOUR - THIS MEANS HIS TOTAL TRAVELLING TIME MUST BE 1 HOUR, BUT HE HAS ALREADY TAKEN 1 HOUR FOR HIS FIRST TRIP. UNLESS HE IS ABLE TO TELEPORT HIMSELF FOR THE SECOND TRIP, HE WILL NEVER BE ABLE TO MAKE IT. SOME SAY THAT HE SHOULD TRAVEL AT 90KM/HOUR FOR THE RETURN TRIP. LET'S WORK IT OUT. FOR THE FIRST TRIP, HE TRAVELLED AT 30KM/HOUR AND COVERED 30KM (HALFWAY TO THE TOWN) IN 1 HOUR. FOR THE SECOND TRIP, IF HE TRAVELLED AT 90KM/HOUR, HE WOULD TAKE 20 MINUTES TO COVER 30KM. HIS TOTAL TRAVELLING TIME WILL BE 1HR AND 20 MINS (80 MINS) AND HE WOULD HAVE TRAVELLED 60KM IN TOTAL. HIS AVERAGE SPEED WOULD BE 45 KM/HOUR AND NOT 60 KM/HOUR YOU WILL HAVE TO SAY, "YOU WILL GIVE ME NEITHER COPPER NOR SILVER COIN." IF IT IS TRUE, THEN YOU WILL GET THE GOLD COIN. IF IT IS A LIE, THEN THE NEGATION MUST BE TRUE, SO THE STATEMENT BECOMES: "YOU WILL GIVE ME EITHER COPPER OR SILVER COIN". THIS WOULD BREAK THE GIVEN CONDITIONS THAT YOU GET NO COIN WHEN LYING. SO THE FIRST SENTENCE MUST BE TRUE THERE MAY MANY POSSIBLE SOLUTIONS, HERE IS A SIMPLE ONE: THE FIRST PERSON TAKES HIS MONTHLY SALARY (LETS SAY $100), ADDS AN ARBITRARY AMOUNT THAT ONLY HE KNOWS (LETS SAY $475) AND WHISPERS THAT NUMBER ($575) TO THE SECOND PERSON. THE SECOND PERSON THEN ADDS HIS MONTHLY SALARY (LETS SAY $150) TO THAT VALUE AND WHISPERS THE NEW TOTAL ($725) TO THE THIRD PERSON. THE THIRD PERSON ADDS IN HIS SALARY, WHISPERS THE NEW TOTAL TO THE FOURTH PERSON AND SO ON UNTIL THE TENTH PERSON ADDS IN HIS SALARY AND WHISPERS THE FINAL TOTAL TO THE FIRST PERSON. THE FIRST PERSON THEN SUBTRACTS HIS ARBITRARY NUMBER FROM THAT TOTAL, DIVIDES BY 10, WHICH PRODUCES THE AVERAGE MONTHLY SALARY FOR THE GROUP WITHOUT ANYONE HAVING TO DIVULGE THEIR SALARY TO ANYONE ELSE