Which choice replaces all as with os?
a
o
for i = 1:length(fruit) fruit{i}(fruit{i} == a) == o; end
for i = 1:length(fruit) fruit{i}(fruit{i} == 'a') == 'o';
for i = 1:length(fruit) fruit(i)(fruit(i) == 'a') == 'o'; end
for i = 1:length(fruit) fruit{i}(fruit{i} == 'a') == 'o'; end